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On Fri, Sep 14, 2018 at 2:37 PM, Noel P. CUA <npcua at donbosco.edu.ph> wrote: > compose your own octave script to calculate the machine > epsilon. Analyze the code. > > epsilon = 1 > DO > IF (epsilon+1<=1) EXIT > epsilon = epsilon/2 > END DO > epsilon = 2 x epsilon > epsilon = 1 while epsilon + 1 > 1: epsilon = epsilon / 2.0 epsilon = 2 * epsilon This will not work in Octave. But maybe it will help you in improving your understanding of the solution.

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