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[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]# best way to remove leading zeros from a tuple like string

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On Monday, May 21, 2018 at 1:05:52 PM UTC-4, Rodrigo Bistolfi wrote: > >>> repr(tuple(int(i) for i in s[1:-1].split(','))) > '(128, 20, 8, 255, -1203, 1, 0, -123)' > > 2018-05-21 4:26 GMT-03:00 Peter Otten <__peter__ at web.de>: > > > bruceg113355 at gmail.com wrote: > > > > > Looking over the responses, I modified my original code as follows: > > > > > >>>> s = "(0000128, 020, 008, 255, -1203,01,-000, -0123)" > > >>>> ",".join([str(int(i)) for i in s[1:-1].split(",")]) > > > '128,20,8,255,-1203,1,0,-123' > > > > I think this looks better with a generator instead of the listcomp: > > > > >>> ",".join(str(int(i)) for i in s[1:-1].split(",")) > > '128,20,8,255,-1203,1,0,-123' > > > > > > -- > > https://mail.python.org/mailman/listinfo/python-list > > I am not familiar with the repr statement. Looking into your response, I like it. There is no need to add-in the parentheses. With the repr statment: >>> bb = repr (tuple (int (i) for i in s [1: -1] .split (','))) >>> bb '(128, 20, 8, 255, -1203, 1, 0, -123)' >>> type(bb) <class 'str'> >>> Without the repr statement: >>> aa = (tuple (int (i) for i in s [1: -1] .split (','))) >>> aa (128, 20, 8, 255, -1203, 1, 0, -123) >>> type(aa) <class 'tuple'> >>> Thanks, Bruce

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