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On Sunday, May 20, 2018 at 6:56:05 PM UTC-4, Ben Bacarisse wrote: > "Michael F. Stemper" <michael.stemper at gmail.com> writes: > > > On 2018-05-20 16:19, Ben Bacarisse wrote: > >> bruceg113355 at gmail.com writes: > >> > >>> Lets say I have the following tuple like string. > >>> (128, 020, 008, 255) > >>> > >>> What is the best way to to remove leading zeroes and end up with the following. > >>> (128, 20, 8, 255) -- I do not care about spaces > >> > >> You could use a regexp: > >> > >> import re > >> ... > >> re.sub(r"(?<![0-9])0+(?=[0-9])", "", "(128, 020, 008, 255)") > >> > >> I post this because I think it works (interesting corner cases are 10005 > >> and 000), > > > > Seeing this makes me realize that mine will eliminate any numbers that > > are all leading zero, including '0'. Also, forms like '-0042' will be > > left unchanged. > > I realised after posting the negatives won't work. Not, I suspect, an > issue for the OP but -0042 can certainly be said to have "leading > zeros". > > > Maybe splitting it into integer forms and sending each through > > str( int( ) ) would be the safest. > > Yup. I gave a version of that method too which handles negative numbers > by accident (by leaving the - in place!). A better version would be > > re.sub(r"-?[0-9]+", lambda m: str(int(m.group(0))), s) > > <snip> > -- > Ben. Looking over the responses, I modified my original code as follows: >>> s = "(0000128, 020, 008, 255, -1203,01,-000, -0123)" >>> ",".join([str(int(i)) for i in s[1:-1].split(",")]) '128,20,8,255,-1203,1,0,-123' If I decide I need the parentheses, this works. >>> "(" + ",".join([str(int(i)) for i in s[1:-1].split(",")]) + ")" '(128,20,8,255,-1203,1,0,-123)' Thanks, Bruce

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