Entering a very large number
Steven D'Aprano <steve+comp.lang.python at pearwood.info> writes:
> On Mon, 26 Mar 2018 02:37:44 +0100, bartc wrote:
>> If I instead initialise C using 'C = int("288712...")', then timings
>> increase as follows:
> Given that the original number given had 397 digits and has a bit length
> of 1318, I must admit to some curiosity as to how exactly you managed to
> cast it to a C int (32 bits on most platforms).
> It is too big for an int, a long (64 bits), a long-long (128 bits) or
> even a long-long-long-long-long-long-long-long-long-long-long-long-long-
> long-long-long (1024 bits), if such a thing even exists.
> So what exactly did you do?
Curiously, the first time I read the original post I also somehow
confused it with C code. But no, the variable is named C, it isn't
written in the C language.