Which part of the loop is it going through in this class frame?
C W <tmrsg11 at gmail.com> writes:
> I am new to OOP.
Welcome, and congratulations on learning Python.
> I'm a bit confused about the following code.
> def print_time(self):
Begins a function definition. The function will receive one argument
(the class instance), and bind the name ?self? to that.
> time = '6:30'
Creates a new text string, and binds the name ?time? to that.
Nothing else ever uses that local name.
Gets the value of ?self.time? ? which means, get the object referred to
by ?self?, look up an attribute named ?time?, and get the object that
name is bound to ? then pass that object as an argument to call ?print?.
The ?print? function will get a text representation of the object, and
emit that text to output.
Nothing else happens in the function; so, the local name ?time? falls
out of scope and is never used.
The function then returns ?None?.
> clock = Clock('5:30')
> I set time to 6:30
No, you bound *a* name ?time? locally inside the ?print_time? function;
but you never used that afterward.
The local name ?time? is a different reference from the ?self.time?
> How does line-by-line execution run inside a frame? How does __init__
After Python creates an instance of a class (using that class's
?__new__? method as the constructor), it then tells the instance to
initialise itself; it calls the object's ?__init__? method as the
So the initialiser, named ?__init__?, is called once the object exists,
but before the caller gets to use that object. The initialiser's job is
to initialise the state of the object; your class does this by setting
the per-instance ?time? attribute.
So, by the time your statement binds the name ?clock? to the new Clock
instance, that instance already has an attribute ?clock.time? with the
That attribute is then available when something else uses that object;
for example, the ?print_time? method accesses that attribute and prints
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