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Ways to make a free variable local to a function?

2018-03-05 17:34 GMT+03:00 Chris Angelico <rosuav at gmail.com>:

> In theory, the CPython bytecode compiler (don't know about other
> Python implementations) could just add these as constants. They'd then
> be bound at either compile time or function definition time (by
> default the former, I think, but the latter would be more useful), and
> be looked up as quickly as locals. I'm not sure how useful this would
> be, though.

With some assumptions, It will be useful for every function call:-)

If PEP 572 [1] were to be accepted, you could do something like this:
> def func(numb):
>     if ((int as int), (float as float)):
>         res = []
>         for i in range(numb):
>             res.append(int(i) + float(i))
>         return res
> Syntactically a bit clunky, but keeps everything inside the function,
> and DOES create local variables. Not sure it's better than your other
> options, but it is another option.

While I'm +0.5 on yours PEP 572 idea, especially in `while` and `if`
statements, this example is an overuse of the proposed syntax ;-) Also it
will add an overhead on every function call, and as you said  -
"Syntactically a bit clunky".

With kind regards,