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On Fri, Aug 4, 2017 at 11:50 AM, Chris Angelico <rosuav at gmail.com> wrote: > My logic was that floating point rounding is easiest to notice when > you're working with a number that's very close to something, and since > we're working with square roots, "something" should be a perfect > square. The integer square root of n**2 is n, the ISR of n**2+1 is > also n, and the ISR of n**2-1 should be n-1. I actually wanted to > start at 2**53, but being an odd power, that doesn't have an integer > square root, so I started at 2**52, which has an ISR of 2**26. A slight irony here is that it actually would have taken your script a *very* long time to get to 2**53 having started at 2**52, even only iterating over the perfect squares.

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