[Python-Dev] checking "errno" for math operaton is safe to determine the error status?
Xin, Peixing wrote:
> On certain platform, expm1() is implemented as exp() minus 1. To calculate
> expm1(-1420.0), that will call exp(-1420.0) then substract 1. You know,
> exp(-1420.0) will underflow to zero and errno is set to ERANGE. As a
> consequence the errno keeps set there when expm1() returns the correct result
This sounds like a bug in that platform's implementation of
expm1() to me. Which platform is it?