[Python-Dev] Can I make marshal.dumps() slower but stabler?
12.07.18 08:43, INADA Naoki ????:
> I'm working on making pyc stable, via stablizing marshal.dumps()
This is not enough for making pyc stable. The order in frozesets still
> Sadly, it makes marshal.dumps() 40% slower.
> Luckily, this overhead is small (only 4%) for dumps(compile(source)) case.
What about the memory consumption?
> So my question is: May I remove unstable but faster code?
> Or should I make this optional and we maintain two complex code?
> If so, should this option enabled by default or not?
My concern is that even if not make it optional, this will complicate
> For example, xmlrpc uses marshal. But xmlrpc has significant overhead
> other than marshaling, like dumps(compile(source)) case. So I expect
> marshal.dumps() performance is not critical for it too.
xmlrpc doesn't use the marshal module. It uses terms marshalling and
unmarshalling, but in different meaning.
> Is there any real application which marshal.dumps() performance is critical?
EVE Online is a well known example.
What if write a script which loads .pyc files and stabilize them? This
could solve the problem for applications which need stable .pyc files,
with zero impact on common use.