Re: Mathmatical Question, Formula to multiply a number by smaller amounts?

oh and about the newsgroup. Well i asked here due to it being
generally program related, it was going to go further into program
talk.. but immediately it seems were getting stuck on the formula.
Well, "we" are due to my lack of explanation skills. Hopefully were
clear now :o

I cant waste anymore time tomorrow so if i have to bite the bullet and
waste some resources i'll have to. I cant afford to sit on my arse
starring at a problem if i do have a workaround. I just hate giving
into problems in the said subject.

On 9/29/05, Zeusbwr <zeusbwr@xxxxxxxxx> wrote:
> In reply Sven, i do not know how to use powers in this case.
>
> For example, a loop was a bad example. There is no "loop". It was just
> a code to give an example. Through time, the user's "dNumber" grows,
> however i want it to grow by a smaller amount each time. There in lies
> the trick, because the only information you have is dNumber, the
> integer "i" does not exist. So using powers with the assumption of
> "times executed" (or somethin similar) would be impossible.
>
> Keep the loop for example, but pretend the integer i didnt exist. How
> could you make dMod multiply ( end product is to increase ) dNumber by
> a smaller amount as dNumber grows.
>
> All the knowledge that is at hand for the formula is how much the
> modifier equals, and the number to modify. There is no knowledge of
> how many times it has been done, there for giving simple Power
> formulas a hard time..
>
> Anyway.. ya.. Any ideas?
>
> On 9/28/05, Sven Devriese <desfen@xxxxxxxxxx> wrote:
> > On Wed, 28 Sep 2005 14:35:08 -0700, Zeusbwr <zeusbwr@xxxxxxxxx> wrote:
> >
> > >double dMod = 1.05; // Modifier
> > >double dNumber = 1; // Number i wish to modify
> > >
> > >for( int i = 0; i < 5; i++ ){
> > >
> > >  dNumber = dNumber * dMod;
> > >  Console.Writeline( "Here is your {0} number: {1}, i, dNumber );
> > >  dMod = dMod * 0.95;
> > >
> > >}
> > >
> > >
> > >Now what i want to do is exactly that, each iteration i want to
> > >multiple a number by a ever smaller number. But the thing is, dMod
> > >cant change.
> > >
> > >Would it be possible to accomplish what is done with that loop,
> > >without modifying dMod?
> >
> > Well, if I understand you correctly you just need to use powers
> > (which are essentially repeated multiplications, if the exponent
> > is an integer).
> >
> > double dMod = 1.05; // Modifier
> > double dNumber = 1; // Number i wish to modify
> >
> > for( int i = 0; i < 5; i++ )
> > {
> >   dNumber = dNumber * (dMod ^ (i + 1));
> >   Console.Writeline( "Here is your {0} number: {1}, i, dNumber );
> > }
> >
> > So, you never modify dMod but you get the same results.
> > My C++ is rusty so you need to look up the
> > exact syntax for raising a number to an integer power.
> > If I recall correctly C(++) has no built-in support for raising
> > a number to a non-integer power but you don't need that.
> > (You can work around that by using exp and ln anyway.)
> >
> > BTW, this is hugely off-topic. In the future you're better off
> > asking such things in any newsgroup that has "math" in its name
> > (e.g. comp.sci.math)
> >
> > HTH
> >
> > Sven
> >
> > ===================================
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>
>
> --
> Zeusbwr[at]gmail.com,
> http://www.google.com/talk/
>
> Project Blog: http://zeusbwr.blogspot.com/
>


--
Zeusbwr[at]gmail.com,
http://www.google.com/talk/

Project Blog: http://zeusbwr.blogspot.com/

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