RE: replacing a node in in-memory XML

This is a multi-part message in MIME format.

In the absence of XQuery updates (still a draft W3C spec) it's quite a bit harder to do this in XQuery than in XSLT: you basically have to organize the recursive walk down the tree copying nodes as you go yourself "by hand". If you are comfortable with XSLT then this is definitely a task where XSLT currently wins. It will get a lot easier with XQuery updates.

 

Michael Kay

http://www.saxonica.com/

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From: talk-bounces-9zRdbLeNGsRBDgjK7y7TUQ@xxxxxxxxxxxxxxxx [mailto:talk-bounces-9zRdbLeNGsRBDgjK7y7TUQ@xxxxxxxxxxxxxxxx] On Behalf Of Robert Walpole
Sent: 06 November 2007 15:05
To: talk-KUd/JJajPrLQT0dZR+AlfA@xxxxxxxxxxxxxxxx
Subject: [xquery-talk] replacing a node in in-memory XML

Hi,

I am trying to figure out the best way to replace a node within an in-memory XML fragment.

For example, lets say I have the following fragment in memory…

<communitygroup>
        <group>
                <name>Test</name>
                <services>
                        <service value="true">2</service>
                </services>
        </group>
</communitygroup>

…and want to replace the services node with the following…

<services>
        <service value="false">1</service>
        <service value="true">2</service>
        <service value="false">3</service>
</services>

Is there a way of doing this in XQuery?

Obviously I could use an XSL transformation, which would give me the result I want, but maybe there is a more efficient way using XQuery?

Thanks
Rob Walpole
Devon Portal Developer
Email robert.walpole-z67GYmfiJqS5nN1hM+u2rQ@xxxxxxxxxxxxxxxx
Web http://www.devonline.gov.uk