Thanks, but in this where do I need to pass the //child
<xsl:template name="split">
<xsl:param name="input-string"/>
<xsl:param name="separator"/>
<xsl:if test="$input-string">
<td><xsl:value-of
select="substring-before($input-string, $separator)/></td>
<xsl:call-template name="split">
<xsl:with-param name="input-string"
select="substring-after($input-string, $separator"/>
<xsl:with-parma name="separator" select="$separator"/>
</xsl:if>
</xsl:template>
-----Original Message-----
From: Raffaele Sena [mailto:raff-wjLoM/DVabRg9hUCZPvPmw@xxxxxxxxxxxxxxxx]
Sent: Wednesday, May 24, 2006 9:17 AM
To: Rajashekaraiah, Rashmi (HP-IT)
Cc: talk-KUd/JJajPrLQT0dZR+AlfA@xxxxxxxxxxxxxxxx
Subject: Re: [xquery-talk] XSL Question
since you posted this on the xquery forum I am assuming you are talking
about XPath 2.0 functionalities.
With XPath 2.0 you can use the fn:tokenize() function to split your
comma-separated list:
fn:tokenize(//child, ',')
returns
('name1', 'name2_pewe', 'name3')
If you want to be XSLT 1.0 - XPath 1.0 compliant you can write a
recursive function that uses fn:substring-before and fn:substring-after:
<xsl:template name="split">
<xsl:param name="input-string"/>
<xsl:param name="separator"/>
<xsl:if test="$input-string">
<td><xsl:value-of
select="substring-before($input-string, $separator)/></td>
<xsl:call-template name="split">
<xsl:with-param name="input-string"
select="substring-after($input-string, $separator"/>
<xsl:with-parma name="separator" select="$separator"/>
</xsl:if>
</xsl:template>
(I didn't really try this but it should be "almost" correct :)
-- Raffaele
Rajashekaraiah, Rashmi (HP-IT) wrote:
> Hi :
>
> I have a XML which looks like :
> <root><child>name1,name2_pewe,name3</child></root>
>
>
> I want to write an xsl to trasnform this to html which should look
> like <html> <body> <table> <tr><td>name1<td><td></td><td></td><tr>
> </table>
> <body>
> </html>
>
> I dono how to write a split function in xslt. please help
>
> Thanks,
> Rashmi
>
> !DSPAM:4473c46a146357962374464!
>
>
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