How do I subtype python internal type that is not part of a module?

I have enhanced my python interpeter to allow subtyping of python functions and 
wish to create
some extension types directly from PyFunction_Type. Unfortunately the type is 
not part of any
module. I have tried the following pyrex code:

# func.pyx
# Useful subtypes of function type.

cdef extern from "python.h":
    ctypedef class function [object PyFunctionObject, type PyFunction_Type]:
        pass
    cdef object PyMethod_New(object func, object self, object type)

cdef class classfunction(function):
    def __get__(self, obj, typ):
        if typ is None:
            typ = type(typ)
        return PyMethod_New(self, typ, type(typ))

cdef class staticfunction(function):
    def __get__(self, obj, typ):
        return self

and it generates the following messages at compile time:

...\func.pyx:5:4: Module name required for 'extern' C class
...\func.pyx:5:4: Type object name specification not allowed for 'extern' C 
class

I cannot give a module name because there is none; the python 'types' and 'new' 
modules are
coded in python and use something like function = type(lambda: None) to get the 
function type.
Even that does not work:

# func.pyx
# Useful subtypes of function type.

cdef extern from "python.h":
    object PyMethod_New(object func, object self, object type)

function = type(lambda: None)
.
.
.

...\func.pyx:7:16: Expected an identifier or literal

Any suggestions?

Lenard Lindstrom 
<len-l@xxxxxxxxx>