Java char *INOUT doesn't OUT

Hi,

I'm using SWIG-1.3.22 on Windows with Java JDK 1.4.2.

I'm trying to wrap a C DLL.  All parameters are passed as pointers (int *, 
double *, and char *).  Most parameters are *INPUT, but some are *INOUT.  The 
int *INOUT and double *INOUT work as expected by turning the parameter into a 
single dimensional array.  But a char *INOUT turns the parameter into a String, 
basically making it a char *INPUT.

I expected the char *INOUT to allow me to pass Strings back and forth via a 
1-dimensional array just like int *INOUT.  Am I off track?  Is there a better 
method to do this?

Through my struggles I also tried the *SBUF and *BYTE methods.  Unfortunately 
neither worked for me.  

The *SBUF caused Access Violations because the char array was a different 
length than the string contained in the StringBuffer.  It was using the 
capacity of a StringBuffer instead of the length of the String contained in it. 
 I tried changing the typemap to use length.  Then I received Access Violations 
when the resulting string was being appended back to the StringBuffer.  I 
wasn't able to figure out why that was failing.

The *BYTE caused garbage to be pasted back into my String.  I was using the 
BYTE method this way:

String s = "0123456789";
byte[] b = s.toByteArray();
int r = DLLWrapper.getResult(b);
s = new String(b);

System.out.println(s);

This resulted in garbage printouts.

Any advice on the best/easiest way to do this?  

Thanks,

Gary


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