[plt-scheme] questions about graphical debugger

Hi,

Two questions about the graphical debugger :

If I debug this procedure :

(define test  (λ (n)

                     (cond  [(> n 3) 'x]

                               [(= n 3) 'y]

                               [(< n 3) 'z])))

(test 1)

1- Why the step cursor goes on 'x and 'y after showing both results to be #f.

2- Why when the step cursor is at the end, the result shown is (test 1) => #<void> and not 'z ?

Thanks.

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Naviguez plus vite avec Internet Explorer 8 Ici.

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