u need to do this for a browser to "show" the image
echo "<img src=\"" . $picture[0] . "\"><p>";
echo "<img src=\"" . $picture[1] . "\"><p>";
echo "<img src=\"" . $picture[2] . "\"><p>";
and as for $picture[0]_name i beleave they are $picture[0][name] and soon
now
"Metin Kale" <m-kale@xxxxxxxxxxxxxxxx> wrote in message
news:5.1.0.14.2.20030522111207.00b989b8@xxxxxxxxxxxxxxxxxxxxxxxxxxxx
>
> Hello all..
>
> I have a web form where people can upload pictures. As my input name in
> file "form.php", I wrote:
>
> <form method=post action=\"submitpics.php\" name=\"frm\"
> enctype=\"multipart/form-data\">
> <input type=\"hidden\" name=\"MAX_FILE_SIZE\" value=\"5000000\">
> <input type=\"file\" name=\"picture[]\">
> <input type=\"file\" name=\"picture[]\">
> <input type=\"file\" name=\"picture[]\">
> <input type=\"submit\">
> </form>
>
>
> That gives me an array called picture with three elements. On the
> receiving end, submitpics.php, I wrote:
>
> echo $picture[0]."<p>";
> echo $picture[1]."<p>";
> echo $picture[2]."<p>";
>
> The echoes gives me the path name instead of displaying the picture. The
> hope is to have a foreach ($picture as $p) feature, but it's not
> working. Also, $picture[0]_name, $picture[0]_size, etc, do not work.
>
> Any help will be much appreciated.
> Thanks,
> Metin
>
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