[SMARTY] Re: How to pass a variable inside a section loop

Look at http://smarty.incutio.com/?page=SmartyFrequentlyAskedQuestions

I think most of your questions will be answered there. For your current
problem just search the page for the "concat" plugin. Then you can use the
following code in your template

{ahref string=$ArrayOfBookmarks[bookmarks]->Name
url="http://www.mypage.com/edit_boomark?bookmarkid=";|concat:$ArrayOfBookmark
s[bookmarks]->Id}

bye,
André


"Mike Potter" <mikep@xxxxxxxxx> schrieb im Newsbeitrag
news:20030128161646.89126.qmail@xxxxxxxxxxxxxxx
> OK, I have found that I can just do
> {ahref string=$ArrayOfBookmarks[bookmarks]->Name} and that will work,
> but now I'm having problems with the URL... What I really want is
> something that combines text and variables, so I have something like this:
> {ahref string=$ArrayOfBookmarks[bookmarks]->Name
>
url="http://www.mypage.com/edit_boomark?bookmarkid=".$ArrayOfBookmarks[bookm
arks]->Id}
> Is it possible to do that?
> Thanks,
> Mike
>
> Mike Potter wrote:
> > Hi all:
> >   I'd like to pass a variable to a function inside of a section loop,
> > but I'm just starting out with smarty, and don't know how to do it.
> > The {ahref} function is one that I downloaded from the extensions
> > directory.
> > I have an array of bookmark objects that I'm passing to my template. I'd
> > like to customize the links that get printed out, but I can't figure out
> > how to get the following to work:
> >
> > {section name=bookmarks loop=$ArrayOfBookmarks}
> >    {ahref string="{$ArrayOfBookmarks[bookmarks]->Name}"
> > url="http://www.oeone.com"}
> > {/section}
> >
> > The above will give an error, since it finds the } at the end of the
> > variable.
> > Any help is appreciated.
> > Thanks,
> > Mike
> >
>



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