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Re: Re: PCA - What next!?: msg#01165

lib.opencv

Subject: Re: Re: PCA - What next!?

in the code inside the PCA.zip file, there is "avg" variable which defines the
images 'pixels average.
I tried to print it to see its value, I can see that avg has some negative
values.. is that normal!
the images from which "avg" is calculated are all gray levels.. that means
values of pixels are between 0..255. So the mean of positive values should be
positive! why do we find negative values for "avg"? is there any explanation?

However, in the HIGUI window showing the projection, I get sometimes black
images for some of the projection.

-Fadi

Parameswaran <cegparamesh@xxxxxxxxx> wrote:
There are many available techniques for face recognition, which can be
found in the face recognition homepage:
www.face-rec.org

The simplest and best approach is PCA or eigenfaces approach, which
can be used either to recognize, or to reduce the dimensionality.

To recognize using the weights, you can use euclidean distance,
Correlation distance, covariance distance, and many other distances
available.

TO save the bounding rectangle of a face, you have to set the Image
Region of Interest(ROI) and save the image.
After saving, reset the ROI.

Regards, :D
Paramesh.

--- In OpenCV@xxxxxxxxxxxxxxx, "kirkl_tamworth" <kirkl_tamworth@...>
wrote:
>
> Hi all,
>
> I have successfully compiled the PCA example provided in the files
> section, which outputs the eigenvalues and such. I have two queries:
>
> 1. Can you help me with where I go from here to perform face-
> recognition? I have 25 face images ready to use and would greatly
> appreciate some help with completing the Eigenface approach.
>
> 2. I have also managed to incorporate the face detection sample into a
> C# application, but I'm not sure how to extract the face from the
> image, given that I know the bounding rectangle. Is there an OpenCV
> function that can do this for me?
>
> My first query is much more important than the second and I would
> really, really appreciate some help with this. Thanks.
>
> Kirk
>






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