Re: block in recursion, Any cure for that kind of situation?

I'm an idiot. That doesn't work either. Why not?

On Jan 22, 2008 10:12 PM, Marcin Tustin <mm3@xxxxxxxxxx> wrote:

For the avoidance of confusion, here is a version with non-guessed syntax:

f := [:a :ff | a ifTrue: [{a . (ff value: (a not) value: ff)}] ifFalse: a].
g := [:a :ff | a ifTrue: [{a . (ff value: (a not) value: ff)}] ifFalse: a].
f value: true value: g.

On Jan 22, 2008 9:35 PM, Marcin Tustin <mm3@xxxxxxxxxx> wrote:

You could add an extra parameter that is another block. Use that parameter as the value of carre in the block. something like:

f := [:a :ff | a ifTrue: [ff (a not) ff] ]
ff: = [:a :ff | a ifTrue: [ff (a not) ff] ]

On Jan 22, 2008 9:10 PM, Hilaire Fernandes <hilaire@xxxxxxxxx> wrote:

I got an error "Attempt to evaluate a block that is already being
evaluated", when I call in recursion a block like

carre := [:s1 :s2 :s3 :s4 :n |
       n >0 ifTrue:
               [carre valueWithArguments:  {(segment value: s1 value: s2).
                        (segment value: s2 value: s3).
                        (segment value: s3 value: s4).
                        (segment value: s1 value: s4).
                        n-1}]]

Hilaire

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