Re: Block evaluation

Soory , of course it must be : x:= [ y:=1. z:=2. z+y. ] .  x value.
and this works.

But why can't I do this:
  x:= [ y:=1. z:=2. z+y. ] .
and evaluate it later?


Regards
Ulli


Am 18.12.2006 um 01:04 schrieb Ulrich Hermann:

> Hi,
>
> I try to evalute the following block, but it doesn't work. I  
> allways got a error message.
>
> | x y z |
> x:= [ y:=1. z:=2. x+y. ] .  x value.  [] in UndefinedObject>>DoIt  
> {[y := 1.  z := 2]}
>
>
> Regards
> Ulli
>
>
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