I can't recall. I actually ran into this problem back in September but I
wasn't able to post to the mailing list from the hosted webmail I was using.
Steve
-----Original Message-----
From: Derek Lamb [mailto:derek@xxxxxxxxxxxxxxxx]
Sent: Wednesday, November 28, 2007 12:43 PM
To: Steve Chapel
Cc: perldl@xxxxxxxxxxxxxxx
Subject: Re: [Perldl] Transpose operator ~ actually applies ~ to each
element
Hi Steve,
I think it's an error in the documentation. PDL::Ops claims that ~
serves as an alias to 'bitnot'.
Is there anywhere else besides PDL::Impatient that you saw a reference
to ~ as a transpose operator?
cheers,
Derek
Steve Chapel wrote:
>
> Running the following program:
>
> #!/usr/bin/perl
> use PDL;
> my $y = pdl([[1,2,3],[4,5,6],[7,8,9]]);
> print ~$y;
>
> using ActivePerl 5.8.8.820 and PDL 2.4.3 gives the following output:
>
> [
> [ -2 -3 -4]
> [ -5 -6 -7]
> [ -8 -9 -10]
> ]
>
> According to the PDL documentation
> <http://pdl.sourceforge.net/PDLdocs/Impatient.html#matrix_functions>,
> "transpose() does what it says and is a convenient way to turn row vectors
> into column vectors. It is bound to the unary operator '~' for
> convenience."
> However, transpose() returns the expected result:
>
> [
> [1 4 7]
> [2 5 8]
> [3 6 9]
> ]
>
> Is this a bug in PDL? An error in the documentation?
>
> Thanks,
> Steve
>
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