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building perl with -D was Re: what happens with $b = $b++?: msg#01886

Subject: building perl with -D was Re: what happens with $b = $b++?

On Sunday, June 30, 2002, at 09:38 , Peter Scott wrote:
[..]

$ perl -Dt -le '$b=$b++'

EXECUTING...

[..]

vladimir: 53:] perl -Dt -le '$b=$b++'
Recompile perl with -DDEBUGGING to use -D switch
vladimir: 54:]

why was it that we opted for or against setting the
DEBUGGING flag at build time????


ciao
drieux

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