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Re: Collection sorting: msg#00188lang.groovy.user
Excellent thanks James I had to use : sortedKeys = keys.sort(){a,b | return a <=> b} if i just used keys.sort(){a,b | return a <=> b} and then iterated through keys it wasnt sorted (keys is the result of a map.keySet() ) , which indicates it doesnt sort the original collection but returns a collection of sorted objects , is that correct? On Mon, 29 Nov 2004 12:14:05 +0000, jastrachan-ee4meeAH724@xxxxxxxxxxxxxxxx <jastrachan-ee4meeAH724@xxxxxxxxxxxxxxxx> wrote: > It can take a closure of 1 argument, in which case the closure acts as > a transformer to the thing which should be compared, or 2 arguments, in > which case the closure acts like a regular comparator. > > people.sort { it.name } > > or > > people.sort { a, b | return a.name <=> b.name } > > > > > On 29 Nov 2004, at 12:09, Babelex wrote: > > Hi all > > > > Just browsing through the groovy reference summary i notice the > > collection.sort(){..} closure support. Obviously on the sheet it > > doesnt actually show one how it operates except to indicate the > > closure acts as a comparator, I just need to work out how to use this > > can anyone give me an example, i was thinking this kind of thing : > > > > myCollectionOfNumbers.sort() {key | return it < key ? -1 : (it == key > > ? 0 : 1)} > > > > to sort a collection of integers > > > > I may be well of base here not being a groovy expert, my actual > > problem is also more complex it's a collection of stings that i wish > > to arrange alphabetically or numerically (even though some arent real > > numbers) > > > > Anyone care to touch me with a clue stick .. > > -- > > regards > > babelex > > > > > > #OpenSource means free to innovate# > > > > > > James > ------- > http://radio.weblogs.com/0112098/ > > -- regards babelex #OpenSource means free to innovate#
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