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Re: no invisible cursor: msg#00171
gnome.gtk+.python
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Subject: |
Re: no invisible cursor |
Ionutz Borcoman wrote:
Le Boulanger Yann wrote:
Ionutz Borcoman wrote:
Le Boulanger Yann wrote:
Ionutz Borcoman wrote:
Hi,
The reference says:
"To make the cursor invisible, use gtk.gdk.Cursor() to create a
cursor with no pixels in it."
When I try to use it, I get an error:
>>> import gtk
>>> gtk.pygtk_version
(2, 4, 1)
>>> c = gtk.gdk.Cursor()
Traceback (most recent call last):
File "<stdin>", line 1, in ?
TypeError: Usage:
gtk.gdk.Cursor(cursor_type)
gtk.gdk.Cursor(display, cursor_type)
gtk.gdk.Cursor(display, pixbuf, x, y)
gtk.gdk.Cusrsor(source, mask, fg, bg, x, y)
>>>
Any idea on what's wrong? Is this not supported in 2.4.1? Is it a bug?
TIA,
Have a look here[1]. you'll find informations on the way to create a
Cursor.
1. http://pygtk.org/pygtk2reference/class-gdkcursor.html
Please read *more carefull* my post. I sent it because the stuff from
[1] are not working. Or am I missing something?
TIA,
gtk.gdk.Cursor() constructor takes one or more arguments, you gave it
none. it's the problem.
Yann
We are running in circles :/
Please read again the docs. They say you can use the gtk.gdk.Cursor()
*with no arguments* to create an invisible cursor. The problem is that
it is not working. So it is the problem of the docs or of the library.
So once again, how do I create an invisible cursor, because
gtk.gdk.Cursor() *with no arguments* is not working, though this was the
supposed way to do it, according to docs.
TIA,
I think the doc suggests you to use an empty pixbuf, not to run
gtk.gdk.Cursors() without arguments.
Maybe i'm wrong :/
Yann
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