The following reply was made to PR c++/2169; it has been noted by GNATS.
From: Daniel Jacobowitz <drow@xxxxxxxxx>
To: intangir@xxxxxxxxx, Thomas McGuire <thomas.mcguire@xxxxxxx>
Cc: gdb-gnats@xxxxxxxxxxxxxxxxxx
Subject: Re: c++/2169: cant step into more than 1 function call on a single
line
Date: Fri, 18 May 2007 16:23:39 -0400
Sorry I didn't see this report earlier.
On Fri, Sep 08, 2006 at 09:23:28PM -0000, intangir@xxxxxxxxx wrote:
> >Description:
> when debugging C++, if there is more than one call (or overloaded operators)
> on a single line, when you step in, it steps in the first call, if its not
> the one you wanted to step into you have to step into every single line in
> that function till you get back out to the original line you want to step
> into..
>
> if you step over then when it returns to the original scope it steps over
> the rest of the line that you needed to step into.. and you miss your chance
> to step into it ;(
Use "finish":
(gdb) start
Breakpoint 1 at 0x40056b: file z.cc, line 13.
Starting program: /space/codesourcery/mips64-build/z
main () at z.cc:13
13 functioniwanttostepinto(givea(), giveb()); // *
(gdb) s
giveb () at z.cc:2
2 int giveb() { return 2; }
(gdb) fin
Run till exit from #0 giveb () at z.cc:2
0x0000000000400570 in main () at z.cc:13
13 functioniwanttostepinto(givea(), giveb()); // *
Value returned is $1 = 2
(gdb) s
givea () at z.cc:1
1 int givea() { return 1; }
(gdb) fin
Run till exit from #0 givea () at z.cc:1
0x0000000000400577 in main () at z.cc:13
13 functioniwanttostepinto(givea(), giveb()); // *
Value returned is $2 = 1
(gdb) s
functioniwanttostepinto (a=1, b=2) at z.cc:6
6 int c = a + b; // try and debug to THIS line. it is a pain
The behavior that "next" steps over other calls on the same line is
unfortunate in your case, but deliberate - it makes some other cases
clearer.
--
Daniel Jacobowitz
CodeSourcery
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