Re: sed to output blocks , which contain a pattern

On Thu, 15 Dec 2005 16:45:04 +0800, Siva Senthil Kumaran
<msivask@xxxxxxxxx> wrote:
>
> Hi Friends,
>
> I need a help in using the sed .
>
> Objective is to search and output the block which contains a pattern
> inside
> the block.
>
> I have a block eg.
>
> BEGIN
> aaaa
> bbbb
> ccc
> ddd
> END
> BEGIN
> aaaa
> bbbb
> ddd
> END
> BEGIN
> aaaa
> bbbb
> ddd
> END
>
> I need to output the block ( from BEGIN to END ) which contains the
> pattern
> "ccc" in it , hence I need the out put to be
>
>
> BEGIN
> aaaa
> bbbb
> ccc
> ddd
> END
>

sed -n '
/BEGIN/{
   :a            # \
   $b            #  |
   N             #  | read block
   /END$/!ba     # /

   /ccc/p        # output the block, if "ccc" is there
}'



-- 
hq00e



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