Re: sed to output blocks , which contain a pattern

--- In sed-users@xxxxxxxxxxxxxxx, "Siva Senthil Kumaran" 
<msivask@xxxx> wrote:
>
> Hi Friends,
> 
> I need a help in using the sed .
> 
> Objective is to search and output the block which contains a 
pattern 
> inside 
> the block.
> 
> 
> I need to output the block ( from BEGIN to END ) which contains the 
> pattern 
> "ccc" in it , hence I need the out put to be
> 


sed -e '
 /^BEGIN$/,/^END$/!d
 /^END$/!{H;/^BEGIN$/h;d;}
 H;g;/ccc/!d
' yourfile

Assuming no whitespaces on your block begin/end lines.






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