Re: sqlite_free_table bug??

Sorry, I got it figured out.  But I think its a good suggestion to add
this in the code.

When sqlite_free_table frees up the memory block, the pointer passed in
is not set back to NULL.  Thus on the second access of
sqlite_free_table, it complains with Segmentation fault.

Should really set the pointer back to NULL before exiting.

Colin


Colin Shum wrote:
> 
> I am having problems with sqlite_free_table.  I tried and cannot call it
> twice in a row.  Is that the same as cant be call with "NULL" pointer?
> 
> using the same pointer as in example, something like this.
> 
> 
> char **result;
> char request_saved[300] = "select * from abc";
> int nrow = 0;
> int ncolumn = 0;
> int rc = 0;
> 
>  void FreeTable( void ) {
>     sqlite_free_table(result);
>   }
> 
> int foo (void) {
>         FreeTable(result);
>         rc = sqlite_get_table(db, request_saved, &result, &nrow, &ncolumn,
> &zErrMsg);
> 
>         return foo;
> }
> 
> Any ideas?
> 
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