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Re: variance aggregate function incorrect? Reference Materials reg create a: msg#00324

Subject: Re: variance aggregate function incorrect? Reference Materials reg create aggregate
Joseph Syjuco <joseph@xxxxxxxxxxxxxxxx> writes:
> i needed the variance function ... i dont know if i introduced the wrong
> parameters or maybe this variance is not the variance that im looking
> for but it doesnt provide the right results

> variance=(nEx^2 - (Ex)^2)/(n(n-1))

That's what I'd expect it to do, all right.  Please define "doesnt
provide the right results".

                        regards, tom lane



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