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Updating a project: msg#00001cms.opengroupware.xmlrpc.devel
Hi, I'm trying to update a project with the following python script #!/usr/bin/python import xmlrpclib HOST="localhost" LOGIN="ogo-admin" PWD = "myPassword" URL="http://%s:%s@%s:80/RPC2" % ( LOGIN, PWD, HOST ) try: server = xmlrpclib.Server(URL) except TypeError, e: print "Catched:", e, "\n" print "Likely reason: you didn't install a basic-auth enabled XML-RPC" print "client library!" sys.exit(1) dict = {} dict['qualifier'] = "number = 'P13940'" project = server.project.fetch(dict)[0] print project['name'] project['name'] = "AAAAAAAAAAAAAAAAA" result = server.project.update(project) but I get the following error Projecte número 2 Traceback (most recent call last): File "./listProjectCodes.py", line 24, in ? result = server.project.update(project) File "/usr/lib/python2.3/xmlrpclib.py", line 1032, in __call__ return self.__send(self.__name, args) File "/usr/lib/python2.3/xmlrpclib.py", line 1313, in __request allow_none=self.__allow_none) File "/usr/lib/python2.3/xmlrpclib.py", line 964, in dumps data = m.dumps(params) File "/usr/lib/python2.3/xmlrpclib.py", line 607, in dumps result = string.join(out, "") File "/usr/lib/python2.3/string.py", line 135, in join return sep.join(words) UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 5: ordinal not in range(128) What's wrong? Thanks. R. Amer Polythecnic University of Catalonia -- OpenGroupware.org XML-RPC xmlrpc@xxxxxxxxxxxxxxxxx http://mail.opengroupware.org/mailman/listinfo/xmlrpc
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